document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377912>Question 377912</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The longer leg of a right triangle is 6 less than 3 times the shorter leg. If the hypotenuse is 26cm., find the length of the two legs. Define the variables, set up your equation and solve. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268532 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let shorter leg be x<BR>\n" );
document.write( "longer leg = 3x-6<BR>\n" );
document.write( "hypotenuse = 26 cm<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Pythagoras theorem <BR>\n" );
document.write( "x^2+(3x-6)^2= 26^2<BR>\n" );
document.write( "x^2+9x^2-36x+36=26^2<BR>\n" );
document.write( "10x^2-36x+36-676=0<BR>\n" );
document.write( "10x^2-36x-640=0<BR>\n" );
document.write( "10x^2-100x+64x-640=0<BR>\n" );
document.write( "10x(x-10)+64(x-10)=0<BR>\n" );
document.write( "(10x+64)(x-10)=0<BR>\n" );
document.write( "c= 10 which is positive<BR>\n" );
document.write( "one leg is 10 cm<BR>\n" );
document.write( "the other leg = 3x-6 = 30-6 =24cm<BR>\n" );
document.write( "..<BR>\n" );
document.write( "m.ananth@hotmail.ca\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );