document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41578>Question 41578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> kx+3y=k-3<BR>\n" );
document.write( "12x+ky=k<BR>\n" );
document.write( "   solve for k </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26853 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> kx+3y=k-3<BR>\n" );
document.write( "12x+ky=k<BR>\n" );
document.write( "   solve for k\r<BR>\n" );
document.write( "\n" );
document.write( "Taking each equation separately to get:<BR>\n" );
document.write( "1st: kx+3y=k-3<BR>\n" );
document.write( "     kx-k=-3y-3<BR>\n" );
document.write( "     k(x-1)=-3(y-1)<BR>\n" );
document.write( "        k = -3(y-1)/(x-1)<BR>\n" );
document.write( "2nd: k=12x+ky<BR>\n" );
document.write( "    k-ky=12x<BR>\n" );
document.write( "    k(1-y)=12x <BR>\n" );
document.write( "    k = 12x/(1-y)\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );