document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377901>Question 377901</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 18. The sum of the first and second number is 15, and the first number is 3 times the third number. Find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268502 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268502\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose these three numbers are a, b, and c. We can write the following equations:\r<BR>\n" );
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document.write( "#1 a+b+c = 18<BR>\n" );
document.write( "#2 a+b = 15<BR>\n" );
document.write( "#3 a = 3c\r<BR>\n" );
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document.write( "If we subtract #2 from #1 we have c = 3. From #3 we have a = 3(3) = 9. Finally, since a+b+c = 18 we plug in our known values for a and c to obtain b = 6. Therefore our three numbers are a = 9, b = 6, c = 3. </SPAN>\n" );
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