document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377891>Question 377891</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the system of equations to solve the following:<BR>\n" );
document.write( "The sum of two numbers is 73. When the smaller number is subtracted from twice the greater number the result is 50. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268497 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let smaller number be x<BR>\n" );
document.write( "the other number be y<BR>\n" );
document.write( "x+y=73.........................1<BR>\n" );
document.write( "2y-x=50........................2<BR>\n" );
document.write( "Add the equations<BR>\n" );
document.write( "3y=123<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "y = 123/3<BR>\n" );
document.write( "y=41..<BR>\n" );
document.write( "plug value of y in (1)<BR>\n" );
document.write( "x+41=73<BR>\n" );
document.write( "-41<BR>\n" );
document.write( "x=73-41<BR>\n" );
document.write( "x=32<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x=32, y =41<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );