document.write( "Question 377863: In 1920 a record for a race was 45.3 seconds. In 1940 it was 44.7 seconds.\r
\n" ); document.write( "\n" ); document.write( "R(t)= the Records of the race and let t = the number of years since 1920.\r
\n" ); document.write( "\n" ); document.write( "1.Find a linear function that fits the Data
\n" ); document.write( "2. Use the function to predict the race 2003, and 2006
\n" ); document.write( "3. Find the year when the record will be 42.5 seconds.\r
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Algebra.Com's Answer #268486 by mananth(16946)\"\" \"About 
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In 1920 a record for a race was 45.3 seconds.
\n" ); document.write( "In 1940 it was 44.7 seconds.
\n" ); document.write( "decrease per year = (45.3-44.7) /20
\n" ); document.write( "=0.6/20
\n" ); document.write( "=0.03 per year.
\n" ); document.write( "R(t) = 45.3-0.03t
\n" ); document.write( "......
\n" ); document.write( "In 2003
\n" ); document.write( "-------------
\n" ); document.write( "R(83)= 45.5-0.03*83
\n" ); document.write( "R(83)=45.5 -2.49
\n" ); document.write( "R(83)=42.81
\n" ); document.write( "In 2003 the record will be 42.81 seconds.
\n" ); document.write( "plug t=86 for 2006
\n" ); document.write( "..
\n" ); document.write( "3.) 42.5 = 45.5 -0.03t
\n" ); document.write( "0.03t=45.5-42.5
\n" ); document.write( "0.03 t = 3
\n" ); document.write( "t = 3/0.03
\n" ); document.write( "t=100
\n" ); document.write( "Add 100 years to 1920= 2020
\n" ); document.write( "In 2020 the recoed will be 42.5 seconds
\n" ); document.write( "m.ananth@hotmail.ca\r
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