document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377858>Question 377858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The incomes of trainees at a local mill are normally distributed with a mean of $1100 and a standard deviation of $150.  What percentage of trainees earn less than $900 a month? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268474 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28X++%3C+900%29+=+P%28%28X+-+mu%29%2Fsigma+%3C+%28900+-+1100%29%2F150+=+-1.33%29 ALIGN=MIDDLE  ALT=\"P%28X++%3C+900%29+=+P%28%28X+-+mu%29%2Fsigma+%3C+%28900+-+1100%29%2F150+=+-1.33%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Then P(X < 900) = P(Z < -1.33) . The percentage is equal to this probability times 100%. Just use a table of standard normal values to find the probability. </SPAN>\n" );
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