document.write( "Question 377756: One number is 1 less than a second number. Twice the second number is 20 less than 4 times the first. Find the two numbers.\r
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document.write( "I have tried dividing 20 by 4 and adding 1 but that still does not work I know the answer is 11 and 12 but I would like to know how to figure it out on my own \n" );
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Algebra.Com's Answer #268449 by scott8148(6628) You can put this solution on YOUR website! let f=first and s=second\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"One number is 1 less than a second number\" ___ f = s - 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"Twice the second number is 20 less than 4 times the first\" ___ 2s = 4f - 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substituting the value of f ___ 2s = 4(s - 1) - 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2s = 4s - 4 - 20 ___ 24 = 2s ___ 12 = s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = (12) - 1 = 11 \n" ); document.write( " |