document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377781>Question 377781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't understand how this problem is solved.  I understand how to come up with the equation but not the answer....\r<BR>\n" );
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document.write( "	\"Which of the following expressions represents the product of 3 less than twice x and 2 more than the quantity 3 times x ?\"\r<BR>\n" );
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document.write( "so, this means (2x-3)(3x+2)= 6x^2 – 5x – 6.  However, I am unsure of how to get the answer...\r<BR>\n" );
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document.write( "Thanks,<BR>\n" );
document.write( "Sharon </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268438 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268438\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2x-3)(3x+2)= 6x^2 – 5x – 6.<BR>\n" );
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document.write( "Use FOIL:<BR>\n" );
document.write( "F means 1st times 1st<BR>\n" );
document.write( "O means last times last<BR>\n" );
document.write( "I means inside times inside<BR>\n" );
document.write( "L means last times last<BR>\n" );
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document.write( "F: 2x times 3x = 6x^2<BR>\n" );
document.write( "O: 2x times 2 = 4x<BR>\n" );
document.write( "I: -3 times 3x = -9x<BR>\n" );
document.write( "L: -3 times 2 = -6<BR>\n" );
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document.write( "Combine these results to get:<BR>\n" );
document.write( "6x^2 -5x -6<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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