document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377702>Question 377702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello.<BR>\n" );
document.write( "     Confuse a bit with this, \r<BR>\n" );
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document.write( "Find and classify the stationary points of the curve y = x^5 - x^3 and hence sketch the curve between the<BR>\n" );
document.write( "points x = -1 and x = 1.\r<BR>\n" );
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document.write( "I Got so far <BR>\n" );
document.write( "Local minimum when x-0.775 and y = -0.186\r<BR>\n" );
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document.write( "Thanks in  advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268418 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268418\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the stationary points you have to get the derivative of y and then equate to zero.  Then y' = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%5E4+-+3x%5E2 ALIGN=MIDDLE  ALT=\"5x%5E4+-+3x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%285x%5E2+-+3%29 ALIGN=MIDDLE  ALT=\"x%5E2%285x%5E2+-+3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 0.  Then x = -0.775, 0, 0.775.  At x = -0.775 there is a local max; at x = 0.775 there is a local min; at x = o there is an inflection point (neither a local max nor a local min; concavity changes from  + to -). </SPAN>\n" );
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