document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377727>Question 377727</A>: <I><SPAN STYLE=\"word-break: break-all;\">  When z = -2 -2i square root 3 what is its \"trigonometric form?\"\r<BR>\n" );
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document.write( "  2 (cos pi/6 + insi pi/6) is what I got. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268415 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268415\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you mean<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=z+=+-2+-+i%282sqrt%283%29%29 ALIGN=MIDDLE  ALT=\"z+=+-2+-+i%282sqrt%283%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Mag+=+sqrt%284+%2B+4%2A3%29+=+4 ALIGN=MIDDLE  ALT=\"Mag+=+sqrt%284+%2B+4%2A3%29+=+4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "theta = arctan(sqrt(3)) in the 3rd Quad = 240º<BR>\n" );
document.write( "--> 4 cis(240)<BR>\n" );
document.write( "= 4(cos(240) + i*sin(240))<BR>\n" );
document.write( "= 4(cos(4pi/3) + i*sin(4pi/3))\r<BR>\n" );
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document.write( " </SPAN>\n" );
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