document.write( "Question 377694:
\n" ); document.write( " please help! i\"m trying to solve:
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\n" ); document.write( " log 2 (x-1) - log 2 (x+3) = log 2 (1/x)
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\n" ); document.write( "This is what i tried, but i think it's wrong: used quotient rule like this: log 2 (x-1/x+3) = log 2 (1/x) OK! NOW WHAT???!!! I'm lost! :(
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Algebra.Com's Answer #268396 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "log 2 (x-1) - log 2 (x+3) = log 2 (1/x)
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document.write( "log 2 (x-1) - log 2 (x+3) - log 2 (1/x)=0
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document.write( "=0
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document.write( "2^0 = (x-1)/(x+3)(1/x)
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document.write( "1 = x(x-1)/(x+3)
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document.write( "(x+3) = x^2 -x
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document.write( "x^2 -2x - 3 = 0
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document.write( "(x-3)(x+1)= 0
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document.write( "(x-3)=0    x = 3
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document.write( "(x+1)= 0   x = -1 reject as a solution
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document.write( "Any solution that makes an argument (or base) zero or negative must be rejected.
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document.write( "log 2 ((-1)-1) - log 2 ((-1)+3) = log 2 (1/(-1))
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