document.write( "Question 377694:
\n" ); document.write( " please help! i\"m trying to solve:
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\n" ); document.write( " log 2 (x-1) - log 2 (x+3) = log 2 (1/x)
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\n" ); document.write( "This is what i tried, but i think it's wrong: used quotient rule like this: log 2 (x-1/x+3) = log 2 (1/x) OK! NOW WHAT???!!! I'm lost! :(
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Algebra.Com's Answer #268390 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
You're almost there.
\n" ); document.write( "\"log%282%2C%28%28x-1%29%2F%28x%2B3%29%29%29=log%282%2C%281%2Fx%29%29\"
\n" ); document.write( "\"%28x-1%29%2F%28x%2B3%29=1%2Fx\"
\n" ); document.write( "Cross multiply,
\n" ); document.write( "\"x%28x-1%29=x%2B3\"
\n" ); document.write( "\"x%5E2-x=x%2B3\"
\n" ); document.write( "\"x%5E2-2x-3=0\"
\n" ); document.write( "\"%28x-3%29%28x%2B1%29=0\"
\n" ); document.write( "Two solutions but only positive arguments are allowed for the log function.
\n" ); document.write( "\"x-3=0\"
\n" ); document.write( "\"highlight%28x=3%29\"
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