document.write( "Question 377675: solve for x: the square root of x + 7 = x - 5. \n" ); document.write( "
Algebra.Com's Answer #268367 by stanbon(75887)\"\" \"About 
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solve for x: the square root of x + 7 = x - 5.
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\n" ); document.write( "sqrt(x+7) = x-5
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\n" ); document.write( "Square both sides to get:
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\n" ); document.write( "x+7 = x^2-10x+25
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\n" ); document.write( "Simplify:
\n" ); document.write( "x^2 -11x + 18 = 0
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\n" ); document.write( "(x-9)(x-2) = 0
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\n" ); document.write( "x = 9 or x = 2
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\n" ); document.write( "Check for extraneous roots:
\n" ); document.write( "sqrt(9+7) = 9-5
\n" ); document.write( "true
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\n" ); document.write( "sqrt(2+7) = 2-5
\n" ); document.write( "false, therefore x=2 is extraneous
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\n" ); document.write( "Solution: x = 9
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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