document.write( "Question 377628: The mean concentration of carbon dioxide is 365 parts per million with a standard deviation of 100 parts per million. Take a sample from 25 cities. Describe the sampling distribution of the sample mean. Find the probability that the sample mean concentration will be above 385 parts per million.\r
\n" ); document.write( "\n" ); document.write( "So far, I am able to figure\r
\n" ); document.write( "\n" ); document.write( "(385-365)/(100/(sqrt 25)) = 0.0527\r
\n" ); document.write( "\n" ); document.write( "At this point, checking the Z table I get the value of 0.06031. I'm not sure where I go from here in finishing this problem. Any help would be greatly appreciated. \n" ); document.write( "

Algebra.Com's Answer #268324 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "(385-365)/(100/(sqrt 25)) = 20/20 = 1 Note: 
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document.write( "Z table or NORMSDIST(1)= .8413
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document.write( "1 - .8413 = .1587 Or 15.87% is the probability that the sample mean concentration will be above 385 parts per million. 
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