document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377620>Question 377620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a problem on my homework that has very little detail in the textbook. I need to know a formula for the following: Two pipes working together can fill a tank in 12hrs. Working alone, the larger one can fill the tank in 18hrs less than the smaller one. How long does it take for the smaller tank working alone? Thank you so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268306 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=time it take larger pipe to fill tank and y =time it take larger pipe to fill tank.<BR>\n" );
document.write( "y=x+18<BR>\n" );
document.write( "1/x + 1/y = 1/12<BR>\n" );
document.write( "1/x + 1/(x+18) = 1/12<BR>\n" );
document.write( "12(x+18)+12x=x(x+18) Multiply by 12x(x+18)<BR>\n" );
document.write( "12x+216+12x=x^2+18x<BR>\n" );
document.write( "x^2-6x-216=0<BR>\n" );
document.write( "x=18 hr<BR>\n" );
document.write( "y=36 hr<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );