document.write( "Question 5276: 2
\n" ); document.write( "\"X+%2B+X+-+12+%3E+0+\": Please help me with this problem.
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Algebra.Com's Answer #2683 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
You can solve inequalities just like you solve equations, with a couple of exceptions: If you multiply or divide by a negative quantity, then you must reverse the order of the inequality sign (<, >, ...)\r
\n" ); document.write( "\n" ); document.write( "x + x - 12 > 0 Simplify.
\n" ); document.write( "2x - 12 > 0 Add 12 to both sides.
\n" ); document.write( "2x > 12 Divide by 2 (Since 2 positive, you don't reverse the order)
\n" ); document.write( "x > 6\r
\n" ); document.write( "\n" ); document.write( "Check the solution by choosing a value of x that is greater than 6 (x > 6).
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