document.write( "Question 377540: A bus arrives at a bus stop at 10am, 24 minutes past ten, and 11am. You arrive
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document.write( "at the bus stop at random times between 10:00am and 11:00am everyday, so all
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document.write( "arrival times are equally likely. Find your expected waiting time for the bus.\r
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document.write( "(Hint: Find the probability that you will arrive at the bus stop between 10:00am
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document.write( "and 24 minutes past ten and find your mean waiting time in that case. Then find
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document.write( "the probability that you will arrive at the bus stop between 24 minutes past 10
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document.write( "and 11am and find your mean waiting time in that case.)\r
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document.write( "Please Help \n" );
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Algebra.Com's Answer #268289 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Probability of 10:00 and 10:24 = 24/60 = .4 mean waiting time 24/2 = 12 min \n" ); document.write( "Probability of 10:24 and 11:00 = 36/60 = .6 mean waiting time 36/2 = 18 min \n" ); document.write( "Expected waiting time = .4*12 + .6*18 = 15.6 min (sum of the individual expectations) \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " \n" ); document.write( " |