document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41531>Question 41531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A construction company i mass-producing picnic pavilions for national parks.  The rafter ends are to be sawed in such a way that they will be vertical when in place.  The front is 8 feet high and the back is 6.5 feet high, and the distance between the front and back is 8 feet.  At what angle should the rafters be cut? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26822 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26822\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The shape of the rafter is as below.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28+400%2C+300%2C+-5%2C+15%2C+-5%2C+15%2C%0D%0Aline%281%2C0%2C9%2C0%29%2C%0D%0Aline%281%2C0%2C1%2C6.5%29%2C%0D%0Aline%289%2C0%2C9%2C8%29%2C%0D%0Aline%289%2C8%2C1%2C6.5%29%2C%0D%0Aline%289%2C6.5%2C1%2C6.5%29%2C%0D%0Alocate%281%2C0%2CA%29%2C%0D%0Alocate%289%2C0%2CB%29%2C%0D%0Alocate%289%2C8%2CC%29%2C%0D%0Alocate%281%2C6.5%2CD%29%2C%0D%0Alocate%289%2C6.5%2CE%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "AD is back side, BC is front side and AB is the distance between the front and back sides.<BR>\n" );
document.write( "So AD = 6.5 ft,BC = 8 ft and AB = 8 ft.<BR>\n" );
document.write( "Hence, the required angle is 10.62 degrees<BR>\n" );
document.write( "Draw a straight line from D parallel to AB which meets BC at E.<BR>\n" );
document.write( "As <DAB and <CBA are both 90 degrees, so is ABCE is a rectangle.<BR>\n" );
document.write( "Hence, BE = AD = 6.5 ft.<BR>\n" );
document.write( "So, CE = BC - BE = 8 - 6.5 = 1.5 ft.<BR>\n" );
document.write( "Also, DE = AB = 8 ft.<BR>\n" );
document.write( "Now, in right angled triangle DEC, let <CDE = x degrees, then<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28x%29+=+CE%2FDE ALIGN=MIDDLE  ALT=\"tan%28x%29+=+CE%2FDE\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.5%2F8 ALIGN=MIDDLE  ALT=\"1.5%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F16 ALIGN=MIDDLE  ALT=\"3%2F16\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Therefore, x = tan inverse (3/16) = 10.62 degrees </SPAN>\n" );
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