document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377480>Question 377480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A big barrel contains 300 L of a 6% solution of lawn fertilizer. How much water should be added to obtain a 5% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268217 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Acid 6 % ----------300 L<BR>\n" );
document.write( "water 0% ---------- x L<BR>\n" );
document.write( "required 5% ------ Total will be x+300<BR>\n" );
document.write( "..<BR>\n" );
document.write( "6*300+0*x=5(x+300)\r<BR>\n" );
document.write( "\n" );
document.write( "1800 =5x+1500<BR>\n" );
document.write( "-1500<BR>\n" );
document.write( "1800-1500=5x<BR>\n" );
document.write( "300 =5x<BR>\n" );
document.write( "/5<BR>\n" );
document.write( "300/5 = x<BR>\n" );
document.write( "60 = x <BR>\n" );
document.write( "60 liters of water<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );