document.write( "Question 377476: Jana can jog 5 miles downhill in the same time that it takes her to jog 3 miles uphill. Find her jogging rate for each way if she jogs downhill 4 mi/h faster than she jogs uphill. \n" ); document.write( "

Algebra.Com's Answer #268212 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
uphill speed = x
\n" ); document.write( "downhill speed = x+4
\n" ); document.write( "..
\n" ); document.write( "time uphill = time downhill
\n" ); document.write( "..
\n" ); document.write( " $\"%283%2Fx%29=%285%29%2F%28x%2B4%29\"$
\n" ); document.write( "cross multiply
\n" ); document.write( "3(x+4)=5x
\n" ); document.write( "3x+12=5x
\n" ); document.write( "5x-3x=12
\n" ); document.write( "2x=12
\n" ); document.write( "/2
\n" ); document.write( "x= 6 mph. up hill speed
\n" ); document.write( "downhill speed = 10 mph
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "

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