document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377425>Question 377425</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Candy worth $0.95/kg was mixed with candy worth $1.85/kg to produce a mixture worth $1.45/kg.  How many kilograms of each kind of candy were used to make 27 kg of the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268197 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268197\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.95x + 1.85(27 - x) = 1.45*27,<BR>\n" );
document.write( "0.95x + 49.95 - 1.85x = 39.15,<BR>\n" );
document.write( "-0.9x = -10.8,<BR>\n" );
document.write( "x = 12 kg, the amount of the $0.95/kg mix, and <BR>\n" );
document.write( "27 - 12 = 15 kg, the amount of the $1.85/kg mix. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );