document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377467>Question 377467</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Clark has a boat that can travel at 15 kph in still water. It can go 140km with the current at the same time it takes to travel 35 km against the current. What is the speed of the river? (Discuss how you find the solution) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268193 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268193\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r = speed of current.<BR>\n" );
document.write( "Then 15 - r = clark's speed against the river,<BR>\n" );
document.write( "15 + r = clark's speed with the current.  Then<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=140%2F%2815%2Br%29+=+35%2F%2815-r%29 ALIGN=MIDDLE  ALT=\"140%2F%2815%2Br%29+=+35%2F%2815-r%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, using the formula T = D/R.<BR>\n" );
document.write( "140(15-r) = 35(15 + r),<BR>\n" );
document.write( "2100-140r = 525 + 35r,<BR>\n" );
document.write( "1575 = 175r,<BR>\n" );
document.write( "r = 9 km/hr, the speed of the river. </SPAN>\n" );
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