document.write( "Question 377466: Janice can encode a report twice as fast as Yobbie. If both girls are working together,they can finish the report in 5 hrs. In how many hrs. can Yobbie encode the entire report if she works alone?\r
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Algebra.Com's Answer #268184 by robertb(5830)\"\" \"About 
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let y = # hours by Yobbie, and j = #hrs by Janice.
\n" ); document.write( "y = 2j, and \"5%281%2Fj+%2B+1%2F%282j%29%29+=+1\". Then \"1%2Fj++%2B0.5%2Fj+=+0.20\".
\n" ); document.write( "\"1.5%2Fj+=+0.20\", or j = 7.5 hrs, for Janice. Yobbie can finish in 2*7.5 = 15 hours.
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