document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=377435>Question 377435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have no idea how to start on this problem,but I do know to solve by making equations for the number of magazines. here's the problem: james sold magazine subscriptions with three prices: $20, $27, and $18.  He sold 6 fewer of the $20 subscriptions than of the $27 subscriptions and sold a total of 31 subscriptions.  If his total sales amounted to $678, how many $18 subscriptions did James sell?. I'm really struggling in algebra right now, so thanks a =  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268182 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a = # $20 mag,<BR>\n" );
document.write( "b =  # $27 mag,<BR>\n" );
document.write( "c =  # $18 mag.\r<BR>\n" );
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document.write( "Then  a = b - 6,<BR>\n" );
document.write( "a+b+c = 31, and <BR>\n" );
document.write( "20a + 27b + 18c = 678.<BR>\n" );
document.write( "Put eqn1 into eqn 2:  b-6 + b + c = 31, or 2b + c = 37.  Then c = 37 - 2b.<BR>\n" );
document.write( "Put eqn1 into eqn 3:  20(b-6) + 27b + 18c = 678, or 47b +  18c = 798.<BR>\n" );
document.write( "Thus we get 47b + 18(37 - 2b) = 798,<BR>\n" );
document.write( "or 11b = 132, or b = 12, the number of $27 mags. c = 13, the number of $18 mags, and a = 6, the number of $20 mags. </SPAN>\n" );
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