document.write( "Question 377444: Dalton's age is half of Chen's. In 10 years Chen's age will be three times what Dalton's was 5 years ago. What are their ages? \n" ); document.write( "
Algebra.Com's Answer #268168 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Dalton's age is half of Chen's. In 10 years Chen's age will be three times what Dalton's was 5 years ago. What are their ages? \n" ); document.write( "... \n" ); document.write( "let Chen's age be x \n" ); document.write( "Dalton's age = x/2 \n" ); document.write( ".. \n" ); document.write( "after 10 years \n" ); document.write( "chen's age = x+10 \n" ); document.write( "Dalton's age = (x/2) +10 \n" ); document.write( ".. \n" ); document.write( "five years ago Dalton was (x/2)-5 years \n" ); document.write( ".. \n" ); document.write( "x+10= 3((x/2)-5) \n" ); document.write( "x+10=3(x-10)/2 \n" ); document.write( "x+10=3x-30/2 \n" ); document.write( "multiply by 2 \n" ); document.write( "2(x+10)=3x-30 \n" ); document.write( "2x+20=3x-30 \n" ); document.write( "2x-3x=-50 \n" ); document.write( "-x=-50 \n" ); document.write( "x= 50 chen's age \n" ); document.write( "Dalton's age = x/2 = 25 years \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |