document.write( "Question 377444: Dalton's age is half of Chen's. In 10 years Chen's age will be three times what Dalton's was 5 years ago. What are their ages? \n" ); document.write( "
Algebra.Com's Answer #268168 by mananth(16946)\"\" \"About 
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Dalton's age is half of Chen's. In 10 years Chen's age will be three times what Dalton's was 5 years ago. What are their ages?
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\n" ); document.write( "let Chen's age be x
\n" ); document.write( "Dalton's age = x/2
\n" ); document.write( "..
\n" ); document.write( "after 10 years
\n" ); document.write( "chen's age = x+10
\n" ); document.write( "Dalton's age = (x/2) +10
\n" ); document.write( "..
\n" ); document.write( "five years ago Dalton was (x/2)-5 years
\n" ); document.write( "..
\n" ); document.write( "x+10= 3((x/2)-5)
\n" ); document.write( "x+10=3(x-10)/2
\n" ); document.write( "x+10=3x-30/2
\n" ); document.write( "multiply by 2
\n" ); document.write( "2(x+10)=3x-30
\n" ); document.write( "2x+20=3x-30
\n" ); document.write( "2x-3x=-50
\n" ); document.write( "-x=-50
\n" ); document.write( "x= 50 chen's age
\n" ); document.write( "Dalton's age = x/2 = 25 years
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\n" ); document.write( "m.ananth@hotmail.ca
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