document.write( "Question 377424: A number is 9 more than the sum of the digits. If the digits are reversed, the new number is 3 less than 4 times the original. \n" ); document.write( "
Algebra.Com's Answer #268138 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A number is 9 more than the sum of the digits. If the digits are reversed, the new number is 3 less than 4 times the original. \n" ); document.write( ".. \n" ); document.write( "let number in ten's place be x & units place be y \n" ); document.write( "number = 10x+y \n" ); document.write( ".. \n" ); document.write( "10x+y= x+y+9 \n" ); document.write( "10x-x+y-y=9 \n" ); document.write( "9x=9 \n" ); document.write( "/9 \n" ); document.write( "x=1 \n" ); document.write( ".. \n" ); document.write( "10y+x = 4(10x+y)-3 \n" ); document.write( "10y+x=40x+4y-3 \n" ); document.write( "10y+x-40x-4y=-3 \n" ); document.write( "6y-39x=-3 \n" ); document.write( "plug value of x \n" ); document.write( "6y-39*1=-3 \n" ); document.write( "6y-39=-3 \n" ); document.write( "+39 \n" ); document.write( "6y=39-3 \n" ); document.write( "6y=36 \n" ); document.write( "/6 \n" ); document.write( "y=6 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |