document.write( "Question 377424: A number is 9 more than the sum of the digits. If the digits are reversed, the new number is 3 less than 4 times the original. \n" ); document.write( "
Algebra.Com's Answer #268138 by mananth(16946)\"\" \"About 
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A number is 9 more than the sum of the digits. If the digits are reversed, the new number is 3 less than 4 times the original.
\n" ); document.write( "..
\n" ); document.write( "let number in ten's place be x & units place be y
\n" ); document.write( "number = 10x+y
\n" ); document.write( "..
\n" ); document.write( "10x+y= x+y+9
\n" ); document.write( "10x-x+y-y=9
\n" ); document.write( "9x=9
\n" ); document.write( "/9
\n" ); document.write( "x=1
\n" ); document.write( "..
\n" ); document.write( "10y+x = 4(10x+y)-3
\n" ); document.write( "10y+x=40x+4y-3
\n" ); document.write( "10y+x-40x-4y=-3
\n" ); document.write( "6y-39x=-3
\n" ); document.write( "plug value of x
\n" ); document.write( "6y-39*1=-3
\n" ); document.write( "6y-39=-3
\n" ); document.write( "+39
\n" ); document.write( "6y=39-3
\n" ); document.write( "6y=36
\n" ); document.write( "/6
\n" ); document.write( "y=6
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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