document.write( "Question 5278: Mr.Ranger is a plumber. He bills his clients for the cost of the call plus the number of hours he works. He earns $470 for a job that takes him 12 hours, whereas he recieves $225 for a 5 hour job.
\n" ); document.write( "a) what is his hourly rate?
\n" ); document.write( "b)what does he charge for the call?
\n" ); document.write( "c)Give an equation that represents his earnings.
\n" ); document.write( "d)Mr.Ranger has jsut finished a contract for which he will be paid $295. How many hours did he work?
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Algebra.Com's Answer #2681 by Earlsdon(6294)\"\" \"About 
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Since you are looking for two unknowns (x = cost of call and y = hourly rate), it seems reasonable to expect to require two equations to solve the problem.
\n" ); document.write( "Let's set up the required equations from the given information:\r
\n" ); document.write( "\n" ); document.write( "1) x + 12y = $470 The cost of the call (x) + 12 hrs @ $y per hour is $470.
\n" ); document.write( "2) x + 5y = $225 The cost of the call (x) + 5 hrs @ $y per hour is $225.\r
\n" ); document.write( "\n" ); document.write( "Rewrite equation 1): x = $470 - 12y and substitute into equation 2).\r
\n" ); document.write( "\n" ); document.write( "2a) ($470 - 12y) + 5y = $225 Simplify and solve for y, the hourly rate.\r
\n" ); document.write( "\n" ); document.write( "$470 - 7y = $225 Subtract $225 from both sides.
\n" ); document.write( "$245 - 7y = 0 Add 7y to both sides.
\n" ); document.write( "$245 = 7y Divide both sides by 7.
\n" ); document.write( "$35 = y This is Mr. Ranger's hourly rate.\r
\n" ); document.write( "\n" ); document.write( "To find the cost of the call, x:\r
\n" ); document.write( "\n" ); document.write( "x = $470 - 12y
\n" ); document.write( "x = $470 - 12($35)
\n" ); document.write( "x = $470 - $420
\n" ); document.write( "x = $50 This is Mr. Ranger's cost of the call.\r
\n" ); document.write( "\n" ); document.write( "The equation that represents his earnings can now be written as:\r
\n" ); document.write( "\n" ); document.write( "E = $50 + $35(y) Where: y is the number of hours spent doing the job.\r
\n" ); document.write( "\n" ); document.write( "Verification is left as an exercise for the student.
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