document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41518>Question 41518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> my question is I need to write the equation for the line satisfying the given information, then write it in slope-intercept form. Graph the equation, and show both of the intercepts. <BR>\n" );
document.write( "Passes through the points (10,42.3)(20,51.5)<BR>\n" );
document.write( "Passes through through the points(100,2.2)(150,1.9)<BR>\n" );
document.write( "passes through the poins(1/2,-1/2) with slope 1/2<BR>\n" );
document.write( "passes through the points(-10.4,0.3)(5,34,000) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26805 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For determination of the equation of a straight line passing through two points, whose coordinates are given, see my answer to this question.\r<BR>\n" );
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document.write( "http://www.algebra.com/cgi-bin/jump-to-question.mpl?question=41158\r<BR>\n" );
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document.write( "For the slope-intercept form of the straight line obtained as above procede as follows. If the equation be ax + by + c = 0 (in general form), then take the whole part of the equation excepting the y-part on the right. Thus you have by = -ax - c. Now divide both sides by the coefficient of y. Thus we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-%28a%2Fb%29%2Ax+-+c%2Fb ALIGN=MIDDLE  ALT=\"y+=+-%28a%2Fb%29%2Ax+-+c%2Fb\"   DISABLED_style= \"max-width:90%; height:auto;\" >. This is the slope intercept form of the st. line ax + by + c = 0 and its slope is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-a%2Fb ALIGN=MIDDLE  ALT=\"-a%2Fb\"   DISABLED_style= \"max-width:90%; height:auto;\" > and point of intersection with y-axis is (0,<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-c%2Fa ALIGN=MIDDLE  ALT=\"-c%2Fa\"   DISABLED_style= \"max-width:90%; height:auto;\" >). To see an example refer to my solution to this question.\r<BR>\n" );
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document.write( "http://www.algebra.com/cgi-bin/jump-to-question.mpl?question=40798\r<BR>\n" );
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document.write( "For expressing the equation of a straight line thus obtained in intercept form to find out the intercepts on the coordinate axes see my solution to this question.\r<BR>\n" );
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document.write( "http://www.algebra.com/cgi-bin/jump-to-question.mpl?question=41324\r<BR>\n" );
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document.write( "Now, to find the equation of a st. line passing through a given point and having a given slope, follow the procedure below.<BR>\n" );
document.write( "Here, we are reqd. to find a st. line whose slope is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and which passes through the point (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F2 ALIGN=MIDDLE  ALT=\"-1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >).<BR>\n" );
document.write( "Let the equation be y = mx + k where m = slope and k = intercept on y-axis.<BR>\n" );
document.write( "So m = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Hence y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >x + k <BR>\n" );
document.write( "or 2y = x + 2k<BR>\n" );
document.write( "Now, this st. line passes through the point (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F2 ALIGN=MIDDLE  ALT=\"-1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >) so its equation must be satisfied by the coordinates of this point.<BR>\n" );
document.write( "Hence, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A%28-1%2F2%29+=+1%2F2+%2B+2k ALIGN=MIDDLE  ALT=\"2%2A%28-1%2F2%29+=+1%2F2+%2B+2k\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2k+=+-1%2F2+-+1+=+-3%2F2 ALIGN=MIDDLE  ALT=\"2k+=+-1%2F2+-+1+=+-3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k+=+%28-3%2F2%29%2F2+=+-3%2F4 ALIGN=MIDDLE  ALT=\"k+=+%28-3%2F2%29%2F2+=+-3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Thus the reqd. equation of the given st. line is <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y+=+x+%2B+2%28-3%2F4%29 ALIGN=MIDDLE  ALT=\"2y+=+x+%2B+2%28-3%2F4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y+=+x+-+3%2F2 ALIGN=MIDDLE  ALT=\"2y+=+x+-+3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or 2x - 4y = 3<BR>\n" );
document.write( "Now, express this equation in intercept form and get the answer.\r<BR>\n" );
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document.write( "Draw the graphs yourself. </SPAN>\n" );
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