document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39554>Question 39554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each equation by first eliminating the fractions<BR>\n" );
document.write( "1/2q - 6 = 1/5q\r<BR>\n" );
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document.write( "Solve each equation by first eliminating the decimal numbers<BR>\n" );
document.write( "0.5b + 3.4 = 0.2b + 12.4\r<BR>\n" );
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document.write( "Solve each equation. If you feel proficient enough, try simplying the process<BR>\n" );
document.write( "4x - 2 = -8 + 5x\r<BR>\n" );
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document.write( "Solve each equation. Identify each as a conditional equation, an inconsistent equation or an identity<BR>\n" );
document.write( "3 - 3(5 - x) = 0\r<BR>\n" );
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document.write( "Solve each equation<BR>\n" );
document.write( "-3 - 4(t - 5) = -2(t + 3) + 11 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26802 by </B><A HREF=/tutors/aboutme.mpl?userid=zeynep><B>zeynep(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=zeynep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2q - 6 = 1/5q <BR>\n" );
document.write( "let's get rid of those fractions by multiplying moth sides by the LCD of 10;<BR>\n" );
document.write( "10.(1/2q - 6) =10.( 1/5q )<BR>\n" );
document.write( "5q-60=2q        add additive inverse of 2q to both sides;<BR>\n" );
document.write( "5q-60-2q=2q-2q<BR>\n" );
document.write( "3q-60=0         add additive inverse of -60 to both sides;<BR>\n" );
document.write( "3q-60+60=0+60<BR>\n" );
document.write( "3q=60           divide both sides by 3;<BR>\n" );
document.write( "q=20\r<BR>\n" );
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document.write( "0.5b + 3.4 = 0.2b + 12.4<BR>\n" );
document.write( "Let's multiply both sides by 10 to eliminate the decimals;<BR>\n" );
document.write( "5b+34=2b+124<BR>\n" );
document.write( "5b+34-2b=2b+124-2b<BR>\n" );
document.write( "3b+34=124<BR>\n" );
document.write( "3b+34-34=124-34<BR>\n" );
document.write( "3b=90         divide both sides by 3;<BR>\n" );
document.write( "b=30\r<BR>\n" );
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document.write( "4x - 2 = -8 + 5x    <BR>\n" );
document.write( "get the variables on the same side by adding additive inverse of 5x to both sides. <BR>\n" );
document.write( "4x - 2-5x = -8 + 5x-5x<BR>\n" );
document.write( "-x-2=-8         add additive inverse of -2 to oth sides to leave the variable, which is x, alone;<BR>\n" );
document.write( "-x-2+2=-8+2<BR>\n" );
document.write( "-x=-6         divide both sides by -1;<BR>\n" );
document.write( "x=6\r<BR>\n" );
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document.write( "3 - 3(5 - x) = 0 <BR>\n" );
document.write( "3-15+3x=0<BR>\n" );
document.write( "-12+3x=0<BR>\n" );
document.write( "-12+3x+12=0+12<BR>\n" );
document.write( "3x=12       divide both sides 3;<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "This equation is a conditional equation. A conditional equation is an equation that is not true for all real numbers but has at leat one real number solution.\r<BR>\n" );
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document.write( "-3 - 4(t - 5) = -2(t + 3) + 11<BR>\n" );
document.write( "-3-4t+20=-2t-6+11<BR>\n" );
document.write( "-4t+17=-2t+5<BR>\n" );
document.write( "-4t+17+2t=-2t+5+2t<BR>\n" );
document.write( "-2t+17=5<BR>\n" );
document.write( "-2t+17-17=5-17<BR>\n" );
document.write( "-2t=-12       divide both sides by -2<BR>\n" );
document.write( "t=6\r<BR>\n" );
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document.write( " </SPAN>\n" );
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