document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=376786>Question 376786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi - Need assistance and my tutor is gone for weekend.  It is graphing <BR>\n" );
document.write( "y = -x^2 and y = -(x-2)^2 + 1\r<BR>\n" );
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document.write( "I did the y = -x^2 it is a perabola that opens down from zero and then goes out to (-1,-1) (1,-1) (-2,-4)(2,-4)  but am confused on the second one - I know that it shifts but uncertain as to formula\r<BR>\n" );
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document.write( "The first time I did it I shifted it to (1,2) then down one and over one. The next time I did it I shifted it to (2,1) and then down. Am stuck\r<BR>\n" );
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document.write( "Thanks for your assistance.\r<BR>\n" );
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document.write( "Carol </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #268018 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=268018\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = -(x-2)^2 + 1\r<BR>\n" );
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document.write( "y=-(x^2-4x+4)+1<BR>\n" );
document.write( "y=-x^2+4x-4+1<BR>\n" );
document.write( "y=-x^2+4x+3<BR>\n" );
document.write( "...<BR>\n" );
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