document.write( "Question 5262:
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document.write( " I could not find any lessons for my brother on Adding and Subtracting algebraic fractions. Could you please help me. Could you also show me how to type in fractions. In this problem x is under x+2 then you add with x+1 under x. Thank you \n" );
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Algebra.Com's Answer #2680 by AnlytcPhil(1806)![]() ![]() You can put this solution on YOUR website! I could not find any lessons for my brother on \n" ); document.write( "Adding and Subtracting algebraic fractions. Could \n" ); document.write( "you please help me. Could you also show me how to \n" ); document.write( "type in fractions. In this problem x is under x+2 \n" ); document.write( "then you add with x+1 under x. Thank you \n" ); document.write( "` \n" ); document.write( "x+2` ` x \n" ); document.write( "--- + --- \n" ); document.write( "`x ` `x+1 \n" ); document.write( "` \n" ); document.write( "Put parentheses around the first numerator and the \n" ); document.write( "second denominator because they contain 2 terms \n" ); document.write( "` \n" ); document.write( "(x+2)` ` `x \n" ); document.write( "----- + ----- \n" ); document.write( "` x` ` `(x+1) \n" ); document.write( "` \n" ); document.write( "The LCD is x(x+1) \n" ); document.write( "The first denominator is x. Thus to become equal to \n" ); document.write( "the LCD it needs to be multiplied by (x+1). But we \n" ); document.write( "must multiply both the numerator and the denominator \n" ); document.write( "by (x+1), so that it will amount to multiplying by 1. \n" ); document.write( "` \n" ); document.write( "(x+2)`(x+1)` ` `x \n" ); document.write( "-----·----- + ----- \n" ); document.write( "` x` `(x+1)` `(x+1) \n" ); document.write( "` \n" ); document.write( "Multiply out the (x+2)(x+1) using the FOIL method, \n" ); document.write( "(x+2)(x+1) = x²+1x+2x+2 = (x²+3x+2). Do not multiply \n" ); document.write( "out the denominator x(x+1), but just leave it as it is \n" ); document.write( "` \n" ); document.write( "(x²+3x+2) ` ` x \n" ); document.write( "--------- + ----- \n" ); document.write( "` x(x+1)` ` (x+1) \n" ); document.write( "` \n" ); document.write( "The second denominator is x. Thus to become equal to \n" ); document.write( "the LCD it needs to be multiplied by x. But we must \n" ); document.write( "multiply both the numerator and the denominator by x, \n" ); document.write( "so that it will amount to multiplying by 1. \n" ); document.write( "` \n" ); document.write( "(x²+3x+2)` ` `x ` `x \n" ); document.write( "--------- + -----·--- \n" ); document.write( "` x(x+1)` ``(x+1)` x \n" ); document.write( "` \n" ); document.write( "Multiply the x by the x, getting x². Do not multiply \n" ); document.write( "out the denominator (x+1)x, but write it as x(x+1) \n" ); document.write( "` \n" ); document.write( "(x²+3x+2)` ` `x² \n" ); document.write( "--------- + ------ \n" ); document.write( "` x(x+1)` ` x(x+1) \n" ); document.write( "` \n" ); document.write( "Now both fractions have the same LCD, so we \n" ); document.write( "combine the numerators and place it over the LCD \n" ); document.write( "` \n" ); document.write( "(x²+3x+2)+x² \n" ); document.write( "------------ \n" ); document.write( "` x(x+1) \n" ); document.write( "` \n" ); document.write( "Remove the parentheses \n" ); document.write( "` \n" ); document.write( "x²+3x+2+x² \n" ); document.write( "---------- \n" ); document.write( "` x(x+1)\r \n" ); document.write( "\n" ); document.write( "Combine the x² and the x², getting 2x² \n" ); document.write( "` \n" ); document.write( "2x²+3x+2 \n" ); document.write( "-------- \n" ); document.write( "`x(x+1) \n" ); document.write( "` \n" ); document.write( "The numerator does not factor, so we are done. \n" ); document.write( "` \n" ); document.write( "Edwin \n" ); document.write( " |