document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41464>Question 41464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (-2/3)+p=1/6\r<BR>\n" );
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document.write( "show work </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26797 by </B><A HREF=/tutors/aboutme.mpl?userid=zeynep><B>zeynep(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=zeynep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26797\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (-2/3)+p=1/6  We add additive inverse of (-2/3) to both sides;\r<BR>\n" );
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document.write( "(-2/3)+p+(2/3)=1/6+(2/3)<BR>\n" );
document.write( "p=5/6\r<BR>\n" );
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document.write( "To solve this kind of equations we get the variable alone on one side by using inverse operations.  </SPAN>\n" );
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