document.write( "Question 376640: Any help would be greatly appreciated on this equation: log(x+84)-log(x+9)=log(x) \n" ); document.write( "
Algebra.Com's Answer #267959 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! log(x+84)- log(x+9) = log(x) \n" ); document.write( ": \n" ); document.write( "Combine the 1st two logs, subtracting means divide \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "therefore \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "x + 84 = x(x+9) \n" ); document.write( "x + 84 = x^2 + 9x \n" ); document.write( "0 = x^2 + 9x - x - 84 \n" ); document.write( "A quadratic equation \n" ); document.write( "x^2 + 8x - 84 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(x+14)(x-6) = 0 \n" ); document.write( "Two solutions \n" ); document.write( "x = -14* \n" ); document.write( "and \n" ); document.write( "x = 6 \n" ); document.write( ": \n" ); document.write( "Checking solutions in original problem' only x = 6 can be a solution \n" ); document.write( ": \n" ); document.write( "log(6+84)- log(6+9) = log(6) \n" ); document.write( "log(90)- log(15) = log(6) \n" ); document.write( "1.954 - 1.176 = .778 \n" ); document.write( ".778 = .778 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "* the solution x=-14 would put a negative value in log(x+9) \n" ); document.write( " |