document.write( "Question 41409: Colin invested $24,000, part at 18% and part at 16%. If the total interest at the end of the year is $4,160, how much did he invest at 18%?\r
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Algebra.Com's Answer #26794 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
x(.18) + (24000 - x)(.16) = 4160
\n" ); document.write( ".18x + 3840 - .16x = 4160
\n" ); document.write( ".02x = 320
\n" ); document.write( "x = 16000
\n" ); document.write( "$16,000 was invested in the 18% interest; now, you should plug:
\n" ); document.write( "(24000 - x)
\n" ); document.write( "24000 - 16000
\n" ); document.write( "8000
\n" ); document.write( "$8,000 was invested in the 16% interest.
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