document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=376654>Question 376654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this: How much 12-karat (50%) gold must be mixed with pure gold to obtain 60 grams of 16-karat (66.6667%) gold? The mass of pure gold is not given. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267932 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much 12-karat (50%) gold must be mixed with pure gold to obtain 60 grams of 16-karat (66.6667%) gold? The mass of pure gold is not given.<BR>\n" );
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document.write( "12-karat (50%) gold.............x grams<BR>\n" );
document.write( "pure gold 100% ................60-x grams<BR>\n" );
document.write( "to obtain 66.6667%.............  60 grams<BR>\n" );
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document.write( "50x+100(60-x)=66.6667*60<BR>\n" );
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document.write( "50x +6000-100x=4000  ( rounded off)<BR>\n" );
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document.write( "-50x=-6000+4000<BR>\n" );
document.write( "-50x=-2000<BR>\n" );
document.write( "/-50<BR>\n" );
document.write( "x=40 grams of 50% gold is to be mixed.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.annath@hotmail.ca </SPAN>\n" );
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