document.write( "Question 376451: To deliver a package, a messenger must travel at a speed of 60mi/h on land and then use a motorboat whose speed is 20mi/h in still water. The messenger goes by land to a dock and then travels on a river against a current of 4mi/h. He reaches the destination in 4.5 hours and then returns to the starting point in 3.5 hours. How far did the messenger travel by land and how far by water?\r
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Algebra.Com's Answer #267892 by ankor@dixie-net.com(22740)\"\" \"About 
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To deliver a package, a messenger must travel at a speed of 60mi/h on land
\n" ); document.write( " and then use a motorboat whose speed is 20mi/h in still water.
\n" ); document.write( " The messenger goes by land to a dock and then travels on a river against a current of 4mi/h.
\n" ); document.write( " He reaches the destination in 4.5 hours and then returns to the starting point in 3.5 hours.
\n" ); document.write( " How far did the messenger travel by land and how far by water?
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\n" ); document.write( "Let x = distance on land
\n" ); document.write( "Let y = distance on water
\n" ); document.write( ":
\n" ); document.write( "Write a time equation and simplify, for each trip
\n" ); document.write( ":
\n" ); document.write( "Land time + water time = total time
\n" ); document.write( "\"x%2F60\" + \"y%2F%28%2820-4%29%29\" = 4.5
\n" ); document.write( "\"x%2F60\" + \"y%2F16\" = 4.5
\n" ); document.write( "Multiply by 60*16 to get rid of the denominators
\n" ); document.write( "16x + 60y = 4.5(960)
\n" ); document.write( "16x + 60y = 4320
\n" ); document.write( "and
\n" ); document.write( "\"x%2F60\" + \"y%2F%28%2820%2B4%29%29\" = 3.5
\n" ); document.write( "\"x%2F60\" + \"y%2F24\" = 3.5
\n" ); document.write( "Multiply by 60*24 to get rid of the denominators
\n" ); document.write( "24x + 60y = 3.5(1440)
\n" ); document.write( "24x + 60y = 5040
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\n" ); document.write( "Use elimination here; subtract 16x + 60y = 4320 from the above equation
\n" ); document.write( "24x + 60y = 5040
\n" ); document.write( "16x + 60y = 4320
\n" ); document.write( "-------------------subtraction eliminates y find x:
\n" ); document.write( "8x = 720
\n" ); document.write( "x = \"720%2F8\"
\n" ); document.write( "x = 90 miles on land
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\n" ); document.write( "Find y using 16x + 60y = 4320
\n" ); document.write( "16(90) + 60y = 4320
\n" ); document.write( "1440 + 60y = 4320
\n" ); document.write( "60y = 4320 - 1440
\n" ); document.write( "60y = 2880
\n" ); document.write( "y = \"2880%2F60\"
\n" ); document.write( "y = 48 miles by water
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\n" ); document.write( "Check these values in the original 1st equation
\n" ); document.write( "90/60 + 48/16 =
\n" ); document.write( "1.5 + 3 = 4.5, confirms our solutions
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