document.write( "Question 41409: Colin invested $24,000, part at 18% and part at 16%. If the total interest at the end of the year is $4,160, how much did he invest at 18%?\r
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Algebra.Com's Answer #26788 by checkley71(8403)\"\" \"About 
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.18X+.16(24000-X)=4160 OR .18X+3840-.16X=4160 OR .02X=320 OR X=16000 INVESTED @ 18% & 8000 INVESTED @ 16% \n" ); document.write( "
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