document.write( "Question 376523: Solution A is 30% alcohol and solution B is 60% alcohol.How much of each solution isneeded to make 100 liters of a solution that is 45% alcohol? \n" ); document.write( "
Algebra.Com's Answer #267872 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Let x represent the amount of the more concentrated 60% solution,
\n" ); document.write( "then (100L - x) would be the amount of the 30% solution
\n" ); document.write( "Mixing together to form the 100L of 45% solution***
\n" ); document.write( ".60x + .30(100L-x) = .45*100L
\n" ); document.write( "Solving for x
\n" ); document.write( ".30x = .15*100L
\n" ); document.write( "x = 50 L, the amount of the more concentrated 60% solution. 50L of the 30% also
\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( ".6*50 + .3*50 = 30 + 15 = 45 = .45*100 \n" ); document.write( "
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