document.write( "Question 376464: A midwestern music competition awarded 41 ribbons. There was 1 less blue ribbon awarded than white and 4 more red awarded than white. How many of each kind were awarded? I have attempted many times and can not figure this one out. \n" ); document.write( "
Algebra.Com's Answer #267846 by ankor@dixie-net.com(22740)\"\" \"About 
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A midwestern music competition awarded 41 ribbons.
\n" ); document.write( " There was 1 less blue ribbon awarded than white and 4 more red awarded than white.
\n" ); document.write( " How many of each kind were awarded?
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"A midwestern music competition awarded 41 ribbons.\"
\n" ); document.write( "b + w + r = 41
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\n" ); document.write( "\"There was 1 less blue ribbon awarded than white\"
\n" ); document.write( "b = w - 1
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\n" ); document.write( "\"and 4 more red awarded than white.\"
\n" ); document.write( "r = w + 4
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\n" ); document.write( "Using the total ribbon equation, replace b and r
\n" ); document.write( "(w-1) + w + (w+4) = 41
\n" ); document.write( "3w + 3 = 41
\n" ); document.write( "3w = 41 - 3
\n" ); document.write( "3w = 38
\n" ); document.write( "w = \"38%2F3\"
\n" ); document.write( "w = 12.67 white, but this can't be true, the solution has to be an integer
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\n" ); document.write( "It's no wonder you are having trouble with this problem, there is a mistake in it.
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\n" ); document.write( "If the total ribbons were 42 instead of 41, if would work just fine
\n" ); document.write( "3w = 42 - 3
\n" ); document.write( "3w = 39
\n" ); document.write( "w = \"39%2F3\"
\n" ); document.write( "w = 13 white ribbons
\n" ); document.write( "and
\n" ); document.write( "13 - 1 = 12 blue ribbons
\n" ); document.write( "and
\n" ); document.write( "13 + 4 = 17 red ribbons, a total of 42
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\n" ); document.write( "This is a good method with all these type of problems\r
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