document.write( "Question 376402:  hi could you please help me to verify this identity
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document.write( "(cot^3 x - tan^3 x)/(sec^2x + cot^2x) = 2cot(2x) \n" );
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Algebra.Com's Answer #267820 by jsmallt9(3758)    ![]() You can put this solution on YOUR website! \n" ); document.write( "First, we can use the pattern, \n" ); document.write( " \n" ); document.write( "Since cot and tan are reciprocals, cot(x)*tan(x) = 1: \n" ); document.write( " \n" ); document.write( "Since \n" ); document.write( " \n" ); document.write( "We can now see that the fraction will reduce: \n" ); document.write( " \n" ); document.write( "leaving: \n" ); document.write( " \n" ); document.write( "Rewriting the left side using sin and cos (a common technique use in these problems) we get: \n" ); document.write( " \n" ); document.write( "Since the right side has one term, we probably want one term on the left side, too. So we will add the fractions. Of course we need common denominators first: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now we can subtract: \n" ); document.write( " \n" ); document.write( "The numerator exactly matches the formula for cos(2x). The denominator is close to sin(2x). sin(2x) = 2sin(x)cos(x). If we multiply both sides by 1/2 we get: \n" ); document.write( " \n" ); document.write( "We can get rid of the fraction in the denominator by multiplying the numerator and denominator by 2: \n" ); document.write( " \n" ); document.write( "giving: \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( " \n" ); document.write( "The fraction is cot(2x): \n" ); document.write( "2cot(2x) = 2cot(2x) Done! \n" ); document.write( "  |