document.write( "Question 376418: Claire is twice as old as her brother Derek. Ten years ago, the sum of their ages was 46. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #267819 by vasumathi(46)\"\" \"About 
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Let the age of Claire = c and the age of her brother = b\r
\n" ); document.write( "\n" ); document.write( "c = 2b ------------>(1)(since Claire is twice as old as her brother)
\n" ); document.write( "Ten years ago the age of Claire = c-10 and the age of her brother = b-10.And the
\n" ); document.write( "sum of these ages = 46.This implies ....
\n" ); document.write( "c-10 + b-10 = 46
\n" ); document.write( "c+b-20 = 46
\n" ); document.write( "c+b = 46+20 (adding 20 on both sides)
\n" ); document.write( "2b + b = 66 (from the (1) above)
\n" ); document.write( "3b = 66
\n" ); document.write( "b = 66/3 = 22
\n" ); document.write( "c = 2b = 2*22 = 44
\n" ); document.write( "So the age of Claire = 44 years
\n" ); document.write( "and the age of her brother = 22 years.\r
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