document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=376377>Question 376377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi!<BR>\n" );
document.write( "     I'm working on a chemisty problem, for which I have the answer, but can't seem to work the equation correctly and am thinking the answer the instructor gave us is incorrect.  Please help!!  What volume of water is needed to prepare 500.0 mL of a 0.250 M Ca(NO3)2 solution from a 5.00 M Ca(NO3)2 solution?  I'm using (M1)(V1)= (M2)(V2)..I changed my mL to L = 0.5 L, then (0.250)(5.00)=(0.5)(V2), then 1.25/0.5 = V2, then V2 = 2.5...The answer from my instructor is 475 mL...Am I wrong?  Thanks!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267798 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let \r<BR>\n" );
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document.write( "M1 = molarity of the final solution, V1 = volume of the final solution (in mL), M2 = molarity of original solution, and V2 = volume of original solution (in mL).\r<BR>\n" );
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document.write( "So this means that\r<BR>\n" );
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document.write( "M1 = 5, V1 = x, M2 = 0.25, and V2 = 500\r<BR>\n" );
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document.write( "Plug all of this into <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=M%5B1%5DV%5B1%5D=M%5B2%5DV%5B2%5D ALIGN=MIDDLE  ALT=\"M%5B1%5DV%5B1%5D=M%5B2%5DV%5B2%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > to get the equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x=0.25%2A500 ALIGN=MIDDLE  ALT=\"5x=0.25%2A500\"   DISABLED_style= \"max-width:90%; height:auto;\" > which becomes <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x=125 ALIGN=MIDDLE  ALT=\"5x=125\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Solve for x to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=125%2F5=25 ALIGN=MIDDLE  ALT=\"x=125%2F5=25\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So because V1 is a volume in mL, the volume of the final solution is 25 mL\r<BR>\n" );
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document.write( "So we have 25 mL of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Ca%28NO%5B3%5D%29%5B2%5D ALIGN=MIDDLE  ALT=\"Ca%28NO%5B3%5D%29%5B2%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" >, which means that there must be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=500-25=475 ALIGN=MIDDLE  ALT=\"500-25=475\"   DISABLED_style= \"max-width:90%; height:auto;\" > mL of water left over.\r<BR>\n" );
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document.write( "Note: I'm not a chemistry specialist so my terminology might be a bit off, but the answer, and the steps taken to get the answer, are correct.  </SPAN>\n" );
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