document.write( "Question 376391: if f varies jointly as q^2 and h, and f = 54 when q = 3 and h = 2, find f when q = 4 and h = 5
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Algebra.Com's Answer #267791 by robertb(5830)\"\" \"About 
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\"f+=+kq%5E2h\", where k is a constant of proportionality. Now from the given,
\n" ); document.write( "\"54+=+k%2A3%5E2%2A2\", or \"54++=+18k\", or k = 3, so that the working equation is \"f+=+3q%5E2h\". When q = 4 and h = 5, \"f+=+3%2A4%5E2%2A5+=+240\".
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