document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=376378>Question 376378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve:\r<BR>\n" );
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document.write( "How long would it take to double your money in an account paying 6% compounded quarterly? (Give answer in years plus days, ignoring leap years).  \r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267786 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume principal P = $100<BR>\n" );
document.write( "Amount A = $200<BR>\n" );
document.write( "rate r = 6%<BR>\n" );
document.write( "time  n = ?<BR>\n" );
document.write( "compounding = quarterly=q<BR>\n" );
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document.write( "n = log(A/P)/(q log[1+(i/q)]).\r<BR>\n" );
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document.write( "n=(log(200/100))/(3*log(1+((0.06)/3))<BR>\n" );
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document.write( "n= 11.67 years<BR>\n" );
document.write( "n= 11 years & 244 days<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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