document.write( "Question 376333: How do we solve the following problem using factorization?\r
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Algebra.Com's Answer #267748 by jim_thompson5910(35256)\"\" \"About 
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\"The sum of the squares of two consecutive integers is 13\" means that \"x%5E2%2B%28x%2B1%29%5E2=13\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B%28x%2B1%29%5E2=13\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx%5E2%2B2x%2B1=13\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx%5E2%2B2x%2B1-13=0\" Subtract 13 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B2x-12=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28x%5E2%2Bx-6%29=0\" Factor out the GCF 2\r
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\n" ); document.write( "\n" ); document.write( "\"2%28x%2B3%29%28x-2%29=0\" Factor \"x%5E2%2Bx-6\" to get \"%28x%2B3%29%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B3=0\" or \"x-2=0\" Use the zero product property\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3\" or \"x=2\" Solve for x.\r
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\n" ); document.write( "\n" ); document.write( "So if \"x=2\", then \"x%2B1=2%2B1=3\" making the two numbers to be 2 and 3. Notice how \"2%5E2%2B3%5E2=4%2B9=13\"\r
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\n" ); document.write( "\n" ); document.write( "Or, if \"x=-3\", then \"x%2B1=-3%2B1=-2\" making the two numbers to be -3 and 2. Notice how \"%28-3%29%5E2%2B%28-2%29%5E2=9%2B4=13\"\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers are\r
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\n" ); document.write( "\n" ); document.write( "-3 and -2\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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