document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=376317>Question 376317</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary, the sum of the measure of the first angle and one forth the second angle is 62.25 degrees find the measure of the angles  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267733 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = one angle, <BR>\n" );
document.write( "90 - x = other angle.  Then <BR>\n" );
document.write( "x + (90-x)/4 = 62.25.  Hence<BR>\n" );
document.write( "x + 22.5 -x/4 = 62.25,<BR>\n" );
document.write( "3x/4 = 39.75,<BR>\n" );
document.write( "0.75x = 39.75,<BR>\n" );
document.write( "x = 53, one angle, and 90 - 53 = 37, the measure of the other angle. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );