document.write( "Question 376239: In 1 year's time, Mrs Farmer will be twice as old as she was 10 years ago. How old is she?
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Algebra.Com's Answer #267648 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! age now = x\r \n" ); document.write( "\n" ); document.write( "age future = x + 1\r \n" ); document.write( "\n" ); document.write( "age past = x - 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "equation: x + 1 = 2(x - 10)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 1 = 2(x - 10)\r \n" ); document.write( "\n" ); document.write( "x + 1 = 2x - 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x - 2x = -1 - 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-x = -21\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -21/-1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 21\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "She is 21 years old.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |