document.write( "Question 375866: how to solve:
\n" ); document.write( "log2x-log(x-7)=log3\r
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Algebra.Com's Answer #267625 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi
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\n" ); document.write( "log2x-log(x-7)=log3
\n" ); document.write( "log2x-log(x-7)-log3=0
\n" ); document.write( "log(2x/3(x-7) = 0
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\n" ); document.write( "10 ^0 = 2x/3(x-7)
\n" ); document.write( "1 = 2x/3(x-7)
\n" ); document.write( "3(x-7)= 2x
\n" ); document.write( "3x - 21 = 2x
\n" ); document.write( "x = 21 \n" ); document.write( "
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