document.write( "Question 376177: Two dice are rolled. What is the probability of getting a sum of at least 5?\r
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Algebra.Com's Answer #267580 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Here is the sample space. It contains 36 possible outcomes:\r\n" );
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document.write( "(1,1)  (1,2)   (1,3)  (1,4)   (1,5)  (1,6)\r\n" );
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document.write( "(2,1)  (2,2)   (2,3)  (2,4)   (2,5)  (2,6)\r\n" );
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document.write( "(3,1)  (3,2)   (3,3)  (3,4)   (3,5)  (3,6)\r\n" );
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document.write( "(4,1)  (4,2)   (4,3)  (4,4)   (4,5)  (4,6)\r\n" );
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document.write( "(5,1)  (5,2)   (5,3)  (5,4)   (5,5)  (5,6)\r\n" );
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document.write( "(6,1)  (6,2)   (6,3)  (6,4)   (6,5)  (6,6)\r\n" );
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document.write( "Now I will color the ones red which have a sum of at least 5:\r\n" );
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document.write( "(1,1)  (1,2)   (1,3)  (1,4)   (1,5)  (1,6)\r\n" );
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document.write( "(2,1)  (2,2)   (2,3)  (2,4)   (2,5)  (2,6)\r\n" );
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document.write( "(3,1)  (3,2)   (3,3)  (3,4)   (3,5)  (3,6)\r\n" );
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document.write( "(4,1)  (4,2)   (4,3)  (4,4)   (4,5)  (4,6)\r\n" );
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document.write( "(5,1)  (5,2)   (5,3)  (5,4)   (5,5)  (5,6)\r\n" );
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document.write( "(6,1)  (6,2)   (6,3)  (6,4)   (6,5)  (6,6)\r\n" );
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document.write( "Count the red ones.  There are 30 of them. (it's easier to count the\r\n" );
document.write( "6 non-red ones and subtract from 36 to get 30).\r\n" );
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document.write( "So the probability of a sum of at least 5 is 30 out of 36, which gives\r\n" );
document.write( "us the fraction \"30%2F36\" which reduces to \"5%2F6\".\r\n" );
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document.write( "Edwin
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