document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=376137>Question 376137</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what rate of interest compounded annually is required to double an investment in 15 years </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267558 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume P=100<BR>\n" );
document.write( "Amount = double = 200<BR>\n" );
document.write( "n= 15 years<BR>\n" );
document.write( "compounded annualy = q=1<BR>\n" );
document.write( "i = rate of interest =?<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Formula for compound interest<BR>\n" );
document.write( "..<BR>\n" );
document.write( "i = q([A/P]^1/nq - 1).\r<BR>\n" );
document.write( "\n" );
document.write( "i=1*((200/100)^(1/15*1)-1)<BR>\n" );
document.write( "i=0.0472<BR>\n" );
document.write( "rate = 4.729%\r<BR>\n" );
document.write( "\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );